Question 998648: An airplane is headed 123 degrees with an air speed of 310 mph with a wind of 40 mph on a bearing of 200 degrees. Find the ground speed to the nearest mph, and the true course of the airplane to the nearest degree?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! An airplane is headed 123 degrees with an air speed of 310 mph with a wind of 40 mph on a bearing of 200 degrees. Find the ground speed to the nearest mph, and the true course of the airplane to the nearest degree?
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Assume the starting point is (0,0)
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Let end point coordinates be (x,y)
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x = 310*cos(123)+40*cos(200) = -206.43
y = 310*sin(123)+40*sin(200) = 246.31
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distance = sqrt[206.43^2+246.31^2] = 321.37 miles
bearing = arctan(246.31/-206.43) = -50 degrees = 310 degrees
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Cheers,
Stan H.
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