SOLUTION: Relative to the circle with the equation x^2+y^2=4 , how has the circle with the equation (x+5)^2+(y-6)^2=4 been shifted? What is the radius of the circle?

Algebra ->  Coordinate-system -> SOLUTION: Relative to the circle with the equation x^2+y^2=4 , how has the circle with the equation (x+5)^2+(y-6)^2=4 been shifted? What is the radius of the circle?      Log On


   

Question 998557: Relative to the circle with the equation x^2+y^2=4 , how has the circle with the equation (x+5)^2+(y-6)^2=4 been shifted? What is the radius of the circle?
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
The general form for the circle is
%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
This has a center at (h,k) and a radius r.
Thus for this example,
(x+5)^2+(y-6)^2=4
the circle is shifted -5 on the x and +6 on the y. Center is (-5,6). Radius = 2.