SOLUTION: Graph the equation y = 2x - 3 on a coordinate plane

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Question 99817: Graph the equation y = 2x - 3 on a coordinate plane
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Graphing Linear Equations
In order to graph y=2%2Ax-3 we only need to plug in two points to draw the line

So lets plug in some points

Plug in x=-3

y=2%2A%28-3%29-3

y=-6-3 Multiply

y=-9 Add

So here's one point (-3,-9)




Now lets find another point

Plug in x=-2

y=2%2A%28-2%29-3

y=-4-3 Multiply

y=-7 Add

So here's another point (-2,-7). Add this to our graph





Now draw a line through these points

So this is the graph of y=2%2Ax-3 through the points (-3,-9) and (-2,-7)


So from the graph we can see that the slope is 2%2F1 (which tells us that in order to go from point to point we have to start at one point and go up 2 units and to the right 1 units to get to the next point) the y-intercept is (0,-3)and the x-intercept is (1.5,0) ,or (3%2F2,0)


We could graph this equation another way. Since b=-3 this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,-3).


So we have one point (0,-3)





Now since the slope is 2%2F1, this means that in order to go from point to point we can use the slope to do so. So starting at (0,-3), we can go up 2 units



and to the right 1 units to get to our next point


Now draw a line through those points to graph y=2%2Ax-3


So this is the graph of y=2%2Ax-3 through the points (0,-3) and (1,-1)