Question 998165: Hi,
My question is:
Find the value of (n) in the following:
n-12 and n+8
that makes each expression divisible by 2, 4, and 9.
Thanks ☺
Answer by Edwin McCravy(20056) (Show Source):
You can put this solution on YOUR website! Hi,
My question is:
Find the value of (n) in the following:
n-12 and n+8
that makes each expression divisible by 2, 4, and 9.
Thanks ☺
I will show that there can be no solution.
If a number is divisible by 4 it is automatically
divisible by 2, So we need only make sure they are
divisible by 4 and 9.
n-12 = 4a = 9b, for some positive integers a and b
a/b = 9/4
So a = 9p and b = 4p for some positive integer p
n-12 = 36p
n = 36p+12
---
n+8 = 4c = 9d, for some positive integers c and d
c/d = 9/4
So c = 9q and d = 4q for some positive integer q
n+8 = 36q
n = 36k-8
---
So n = 36p+12 = 36q-8
20 = 36q-36p
20 = 36(q-p)
20/36 = q-p
5/9 = q-p
But q-p is an integer and 5/9 is not.
Therefore there is no possible solution for n.
Edwin
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