SOLUTION: f (x)= 4x^4 +21x^3 + 33x^2 + 147x + 35

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: f (x)= 4x^4 +21x^3 + 33x^2 + 147x + 35      Log On


   

Question 998078: f (x)= 4x^4 +21x^3 + 33x^2 + 147x + 35
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

f+%28x%29=+4x%5E4+%2B21x%5E3+%2B+33x%5E2+%2B+147x+%2B+35......factor completely, write 33x%5E2 as 28x%5E2%2B5x%5E2
f+%28x%29=4x%5E4%2B28x%5E2%2B21x%5E3+%2B147x%2B5x%5E2%2B35+.......group
f+%28x%29=%284x%5E4%2B28x%5E2%29%2B%2821x%5E3+%2B147x%29%2B%285x%5E2%2B35+%29.......factor
f+%28x%29=4x%5E2%28x%5E2%2B27%29%2B21x%28x%5E2+%2B7%29%2B5%28x%5E2%2B7+%29
f+%28x%29=%284x%5E2%2B21x%2B5%29%28x%5E2%2B7%29
f+%28x%29=+%28x%2B5%29+%284x%2B1%29+%28x%5E2%2B7%29
zeros:
0=+%28x%2B5%29+=>x=-5
0=++%284x%2B1%29+=>x=-1%2F4
0=++%28x%5E2%2B7%29=>x%5E2=-7=>x=sqrt%28-7%29=>x=i%2Asqrt%287%29 and x=-i%2Asqrt%287%29