SOLUTION: 4xsquared+3x=5 quadratic formula

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Question 998038: 4xsquared+3x=5 quadratic formula
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
4xsquared+3x=5 quadratic formula
4x^2 + 3x - 5 = 0
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 4x%5E2%2B3x%2B-5+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%283%29%5E2-4%2A4%2A-5=89.

Discriminant d=89 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-3%2B-sqrt%28+89+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%283%29%2Bsqrt%28+89+%29%29%2F2%5C4+=+0.804247641507075
x%5B2%5D+=+%28-%283%29-sqrt%28+89+%29%29%2F2%5C4+=+-1.55424764150708

Quadratic expression 4x%5E2%2B3x%2B-5 can be factored:
4x%5E2%2B3x%2B-5+=+%28x-0.804247641507075%29%2A%28x--1.55424764150708%29
Again, the answer is: 0.804247641507075, -1.55424764150708. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+4%2Ax%5E2%2B3%2Ax%2B-5+%29