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Question 99791: Find for consecutive integers such that the sum of the second and the fourth is 17 less than thrice the first.
Answer by Adam(64)   (Show Source):
You can put this solution on YOUR website! 4 consecutive integers. we can denote them n , n+1 , n+2 and n+3. We know that sum of second and fourth n+1+n+3 should be 17 less then thrice the first 3n-17.We get linear equation 2n+4=3n-17 /-2n
4=3n-2n-17 /+17
4+17 = n
n = 21
Thus our integers are 21, 22, 23 and 24.
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