SOLUTION: Can you please help me with this question? Write an equation for the line that passes through (5, -4) and is perpendicular to the graph of 5x-2y=-6. this is my work so far: 2y=5

Algebra ->  Rational-functions -> SOLUTION: Can you please help me with this question? Write an equation for the line that passes through (5, -4) and is perpendicular to the graph of 5x-2y=-6. this is my work so far: 2y=5      Log On


   



Question 997680: Can you please help me with this question? Write an equation for the line that passes through (5, -4) and is perpendicular to the graph of 5x-2y=-6. this is my work so far:
2y=5x+6 then y=5/2 x + 3
I can't figure out how to find the perpendicular equation. Can you please help me with this part?
Thanks!

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
You have the correct given equation, better stated as y=%285%2F2%29x%2B3.

Slope?
What do you know about slopes of perpendicular lines?
Do you want to know y-intercept for the line you are looking for? Do you like to use the point-slope form equation for a line?



Finished answer equivalent to highlight%282x%2B5y=-5%29

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

Can you please help me with this question? Write an equation for the line that passes through (5, -4) and is perpendicular to the graph of 5x-2y=-6. this is my work so far:
2y=5x+6 then y=5/2 x + 3
I can't figure out how to find the perpendicular equation. Can you please help me with this part?
Thanks!
Your equation is correct! Good job!!
The equation that's perpendicular to y+=+%285%2F2%29x+%2B+3 will have a slope, or m of: -+2%2F5
Using the slope, or m+=+-+2%2F5, the point: (5, - 4), and the point-slope form: y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29, we get:
y+-+-+4+=+-%282%2F5%29%28x+-+5%29
y+%2B+4+=+-+%282%2F5%29x+%2B+2
y+=+-+%282%2F5%29x+%2B+2+-+4
Perpendicular equation is then: highlight_green%28y+=+-%282%2F5%29x+-+2%29, or highlight_green%282x+%2B+5y+=+-+10%29