SOLUTION: 9x^3-7x^2+441x-343=0

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Question 997649: 9x^3-7x^2+441x-343=0
Answer by ikleyn(52795) About Me  (Show Source):
You can put this solution on YOUR website!
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9x%5E3-7x%5E2%2B441x-343 = 0.

Group:

9x%5E3-7x%5E2%2B441x-343 = %289x%5E3+%2B+441x%29 - %287x%5E2+%2B+343%29 = 9x%2A%28x%5E2+%2B+49%29 - 7%2A%28x%5E2+%2B+49%29 = %289x+-+7%29%2A%28x%5E2+%2B+49%29.

The roots are x = 7%2F9, 7i and -7i.
The last two are complex numbers.