SOLUTION: Eighty ounces of a 50% gold alloy are mixed with 20 oz of a 10% gold alloy. Find the percent concentration of the resulting gold alloy.

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Eighty ounces of a 50% gold alloy are mixed with 20 oz of a 10% gold alloy. Find the percent concentration of the resulting gold alloy.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 997462: Eighty ounces of a 50% gold alloy are mixed with 20 oz of a 10% gold alloy. Find the percent concentration of the resulting gold alloy.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Eighty ounces of a 50% gold alloy are mixed with 20 oz of a 10% gold alloy. Find the percent concentration of the resulting gold alloy.
percent concentration of the resulting gold
50%*80+10%*20=(40+2)/100=42%
percent concentration of the resulting gold =42%