SOLUTION: Gary can finish an engineering work in 8 hours. Clint can finish the same work in 6 hours. After 2 hours working together, Gary left for lunch and Clint finished the job. How long

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Gary can finish an engineering work in 8 hours. Clint can finish the same work in 6 hours. After 2 hours working together, Gary left for lunch and Clint finished the job. How long       Log On


   

Question 997209: Gary can finish an engineering work in 8 hours. Clint can finish the same work in 6 hours. After 2 hours working together, Gary left for lunch and Clint finished the job. How long does it take Clint to finish the job?
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
Engineers     rate             time        work
GARY          1/8              
CLINT         1/6               t          (1/6)t
BOTH          (1/8+1/6)         2          (1/8+1/6)*2
Total                                       1


RT=W, basic uniform rate relationship to do work;
This example uses W=1, for ONE WHOLE WORK or JOB.

Most logical next step is form equation t%2F6%2B2%2F8%2B2%2F6=1
t%2F6%2B1%2F4%2B1%2F3=1, LCD is 12,
12%28t%2F6%2B1%2F4%2B1%2F3%29=12
2t%2B3%2B4=12
2t=12-7
2t=5
highlight%28t=2%261%2F2%29
Find t.