SOLUTION: Solution A is 10% sugar while solution B is 30% sugar. A student wants to have a 50 liter of solutions A and B that is 18% sugar. How many liters of each solution should be used?

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Question 997131: Solution A is 10% sugar while solution B is 30% sugar. A student wants to have a 50 liter of solutions A and B that is 18% sugar. How many liters of each solution should be used?
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
Solution A is 10% sugar while solution B is 30% sugar. A student wants to have a 50 liter of solutions A and B that is 18% sugar. How many liters of each solution should be used?
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%280.1%2Ax+%2B0.3%2A%2850-x%29%29%2F50 = 0.18.

Numerator is the amount of the soluted sugar, x is a volume of the 10% solution.

0.1x + 0.3*(50-x) = 0.18*50,

0.1x - 0.3x = 9 - 15,

-0.2x = -6,

x = 6%2F0.2 = 30.

Answer. 30 liters of 10% solution and 50-30 = 20 liters of 30% solution.


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Solution A is 10% sugar while solution B is 30% sugar. A student wants to have a 50 liter of solutions A and B that is 18% sugar. How many liters of each solution should be used?
Amount of 10% sugar solution needed: highlight_green%2830%29 L

Amount of 30% sugar solution needed: 50 - 30, or highlight_green%2820%29 L

You can do the check!!