SOLUTION: Three consecutive even integers have the property that when the difference between the first and twice the second is found, the result is eight more than the third. Find the three

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Question 997115: Three consecutive even integers have the property that when the difference between the first and twice the second is found, the result is eight more than the third. Find the three consecutive even integers.
Found 3 solutions by CubeyThePenguin, MathTherapy, josgarithmetic:
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive even integers = n-2, n, n+2

n - (n-2) = (n+2) + 8
2 = n + 10
n = -8

The integers are -10, -8, and -6.

Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!

Three consecutive even integers have the property that when the difference between the first and twice the second is found, the result is eight more than the third. Find the three consecutive even integers.
INTEGERS are NOT as stated by the other person!! 


Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
system%28Integers%2Cn%2Cn%2B2%2Cn%2B4%29


2%28n%2B2%29-n=8%2B%28n%2B4%29-----------------the second part of the description

2n%2B4-n=n%2B12

n%2B4=n%2B12
(Maybe I am misreading something but the description seems to be nonsens.)