SOLUTION: 1.Given that f(x) is a cubic function with zeros at -3, 0, and 6, find an equation for f(x) given that f(8) = 9. f(x)=__________
2. Suppose p(x) is a polynomial with real coeffici
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-> SOLUTION: 1.Given that f(x) is a cubic function with zeros at -3, 0, and 6, find an equation for f(x) given that f(8) = 9. f(x)=__________
2. Suppose p(x) is a polynomial with real coeffici
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Question 996805: 1.Given that f(x) is a cubic function with zeros at -3, 0, and 6, find an equation for f(x) given that f(8) = 9. f(x)=__________
2. Suppose p(x) is a polynomial with real coefficients that bounces off the x-axis at 47, bounces off the x-axis at -28, and breaks through the x-axis at 91. If p(-9-7i)=p(-6+4i)=0. what is the smallest possible degree that p(x) could have?
You can put this solution on YOUR website! f(x)=a(x+3)(x)(x-6)=a(x^3-3x^2-18x)
f(8)=9, so (8,9) is a point
9=a(x^3-3x^2-18x)
9=a(512-192-144)
9=176a
a=(9/176)
(9/176)(x^3-3x^2-18x)
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Complex roots are conjugate.
2 complex roots, so 4 altogether there.
2 bounces, so that is 4 more at least.
1 crossing.
degree 9 minimal.
