SOLUTION: Find two consecutive integers that ten more than twice the smaller is seven less than three times the larger.

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Question 996635: Find two consecutive integers that ten more than twice the smaller is seven less than three times the larger.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

let two consecutive integers be: x and x%2B1
ten more than twice the smaller :2x%2B10
is :=
seven less than three times the larger: 3%28x%2B1%29-7
so, we have 2x%2B10=3%28x%2B1%29-7........solve for x
2x%2B10=3x%2B3-7
2x%2B10=3x-4
4%2B10=3x-2x
x=14=> smaller number
then larger number is x%2B1=15
check:
2x%2B10=3%28x%2B1%29-7
2%2A14%2B10=3%2815%29-7
28%2B10=45-7
38=38