You can put this solution on YOUR website! how can 1946 be written as the sum of four consecutive whole numbers?
:
n + (n+1) + (n+2) + (n+3) = 1946
Combine like terms
4n + 6 = 1946
subtract 6 from both sides
4n = 1946 -6
4n = 1940
Divide both sides by 4
n = 1940/4
n = 485 is the first of the 4 consecutive numbers
:
485 + 486 + 487 + 488 = 1946