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Question 996489: one number is 11 more than another number. find the two numbers if three times the larger number exceed four times the smaller number by 4?
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! Let's call one number x and another number y.
one number is 11 more than another number:
x = y+11 <---Value of x
three times the larger number exceed four times the smaller number by 4?
3x+4 = 4y Now, in this equation, let's replace x with the value of x:
3(y+11)+4= 4y Multiply on left
3y+33+4= 4y Add numbers on left and subtract 3y on both sides
37= 1y and we can write this simply as
y= 37
Proof
One number is 11 more than another number, and since 37 is "another number", 37+11= "one number", 37+11= 48 Next, the problem says, three times the larger number exceed four times the smaller number by 4:
4*37-3*48= 4 Multiply
148-144= 4 We've got the right answer
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