SOLUTION: An 112 ounces mixture is created by combining two ethylene solutions. One solution is 10% ethylene and the other is 2% ethylene. If the final mixture is comprised of a 7.9% ethylen

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Question 996277: An 112 ounces mixture is created by combining two ethylene solutions. One solution is 10% ethylene and the other is 2% ethylene. If the final mixture is comprised of a 7.9% ethylene solution, then how much of the 10% solution was used?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
What kind of solution is this? More to the point, what is the solvent for this "ethylene" solution? Is this a gas mixture? "Ounces"; really?

Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!

An 112 ounces mixture is created by combining two ethylene solutions. One solution is 10% ethylene and the other is 2% ethylene. If the final mixture is comprised of a 7.9% ethylene solution, then how much of the 10% solution was used?
Let amount of 10% ethylene be T

Then amount of 2% ethylene = 112 – T

We then get: .1T + .02(112 – T) = .079(112)

.1T + 2.24 - .02T = 8.848

.1T - .02T = 8.848 – 2.24

.08T = 6.608

T, or amount of 10% ethylene = 6.608%2F.08, or highlight_green%2882.6%29 oz