SOLUTION: Find the inverse of y=f(t)=sqrt(5t)+7 here are my calculation for this problem, and I would appreciate if you could point out if I did a mistake. f(t)=sqrt(5t)+7 f(y)=sqrt(5

Algebra ->  Inverses -> SOLUTION: Find the inverse of y=f(t)=sqrt(5t)+7 here are my calculation for this problem, and I would appreciate if you could point out if I did a mistake. f(t)=sqrt(5t)+7 f(y)=sqrt(5      Log On


   

Question 996096: Find the inverse of y=f(t)=sqrt(5t)+7
here are my calculation for this problem, and I would appreciate if you could point out if I did a mistake.
f(t)=sqrt(5t)+7
f(y)=sqrt(5x)+7
x=sqrt(5y)+7
x-7=sqrt(5y)
(x-7)^2=5y
(x-7^2/5)=y
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The only error I see is in the last line. It should be y = ( (x-7)^2 )/5. All of (x-7)^2 is over the 5.

Keep in mind that because the range of sqrt(5t)+7 is [7,infinity), the domain of the inverse is going to be [7,infinity)