Question 996068:  The measure of angle A is 30 degrees less than twice the measure of angle B . Find the measure of each angle of the parallelogram .  
 Answer by Theo(13342)      (Show Source): 
You can  put this solution on YOUR website! A = 2 * B - 30 
in a parallelogram, opposite angles are equal. 
sum of the angles in a parallelogram is 360 degrees. 
this means that 2A + 2B = 360. 
divide both sides of this equation by 2 to get: 
A + B = 180.
 
 
if A + B = 180 and A = 2 * B - 30, then 2 * B - 30 + B = 180.
 
 
combine like terms to get 3 * B - 30 = 180. 
add 30 to both sides of this equation to get 3 * B = 210. 
divide both sides of this equation by 3 to get B = 70 degrees.
 
 
if B = 70 degrees, then A must be equal to 110 degrees because 2 * 70 - 30 = 110.
 
 
if your parallelogram is ABCD (points are clockwise from top left), then:
 
 
angle A = 110 
angle B = 70 
angle C = 110 
angle D = 70
 
 
sum of the angles is 220 + 140 = 360 as it should be. 
angle A = angle C because opposite angles of a parallelogram are equal. 
likewise angle B = angle D. 
angle A is supplementary to angle B because adjacent angles of a parallelogram are supplementary. 
likewise angle B is supplementary to angle C 
likewise angle C is supplementary to angle D 
likewise angle D is supplementary to angle A.
 
 
 
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