Question 995910: For what values of b will x^2+bx+1=0 have real solutions?
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! For what values of b will x^2+bx+1=0 have real solutions?
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Use the discriminant::
Evaluate:: b^2 - 4ac > 0
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b^2 -4*1*1 > 0
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(b-2)(b+2) > 0
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If b-2 > 0, b > 2
If b+2 > 0, b > -2
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To meet both conditions b must be > 2
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Cheers,
Stan H.
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