SOLUTION: Hello. I need some help with probability problems. I have never had a class on statistice and probability so I am completely lost on the formulas I need to use to sole these probl

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Question 995814: Hello. I need some help with probability problems. I have never had a class on statistice and probability so I am completely lost on the formulas I need to use to sole these problems.
Email. r.jennings3@aol.com
1. what is the formula for probability problem which will solve the probability of 86 students of 100 following directions?
2. How do I find the probability of single- randomly selected shopper for buying clothes or electronics but not both? 500 customers, 320 shopped for clothes, 295 shopped for electronics, 175 shopped for both. Part B how can these numbers be shown in a venn diagram with four regions i.e..
2 over lapping circles inside a squre the first circle is RI the second Circle RIII the over lap RII and the outside square RIV.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
1. what is the formula for probability problem which will solve the probability of 86 students of 100 following directions?
Formula: P(follow directions) = (# who follow directions)/(total # of students)
Ans: P(follow) = 86/100
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2. How do I find the probability of single- randomly selected shopper for buying clothes or electronics but not both? 500 customers, 320 shopped for clothes, 295 shopped for electronics, 175 shopped for both.
Part B how can these numbers be shown in a venn diagram with four regions i.e.
Sketch a rectangle with two intersecting circles inside the rectangle.
Label the circles:: clothes ; electronics
175 is the number in the intersection of the 2 circles
320-175 = 145 is the number in clothes but not in the intersection
295-175 = 120 is the number in electronics but not in the intersection
P(clothes or elect) = P(clothes) + P(electronics)-P(clothes AND electronics)
= (320+295-175)/500 = 440/500 = 11/25
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Cheers,
Stan H.
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