SOLUTION: a chemist, mixed 40 ml of 8% acid with 60 ml of 12% acid solution. she used a portion of this solution and replaced it with distilled water. If the new solution tested 5.2% acid,

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: a chemist, mixed 40 ml of 8% acid with 60 ml of 12% acid solution. she used a portion of this solution and replaced it with distilled water. If the new solution tested 5.2% acid,       Log On

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Question 995710: a chemist, mixed 40 ml of 8% acid with 60 ml of 12% acid solution. she used a portion of this solution and replaced it with distilled water. If the new solution tested 5.2% acid, how much of the original mixture did she use?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
First mixture:
%2840%2A8%2B60%2A12%29%2F100=10.4%2Apercent, and this is 100 milliliters of solution.

The Next mixture:
v volume was removed and replaced with distilled water, and this now became 5.2% acid. Find v.
%28100%2A0.104-0.104v%29%2F100=0.052;
Volume of starting solution stays the same 100 milliliters; just the concentration changes; this equation is setup in decimal fractions instead of percents. Solve for v.