Question 995590: given tanθ = √5, find secθ and cotθ in quadrant III
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! given tanθ = √5, find secθ and cotθ in quadrant III
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Note: x and y are both negative in QIII
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By definition, tan = y/x
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So, y = -sqrt(5) and x = -1
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Then, r = sqrt[(sqrt(5))^2+(1)^2] = sqrt[5+1] = sqrt(6)
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Ans: sec(t) = r/x = -sqrt(6) and cot(t) = x/y = 1/sqrt(5) = (1/5)sqrt(5)
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Cheers,
Stan H.
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