SOLUTION: Length of a rectangle is 5 cm less then twice its breadth, if the length is decreased by 3 cm and breadth increased by 2 cm the perimetre is 72. find the area of original rectangle
Question 995567: Length of a rectangle is 5 cm less then twice its breadth, if the length is decreased by 3 cm and breadth increased by 2 cm the perimetre is 72. find the area of original rectangle. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Let L & W be the original length and width
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Write an equation for each statement.
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Length of a rectangle is 5 cm less then twice its breadth,
L = 2W - 5
if the length is decreased by 3 cm and breadth increased by 2 cm the perimeter is 72.
2(L-3) + 2(W+2) = 72
Divide equation by 2
L - 3 + W + 2 = 36
L + W - 1 = 36
L + W = 37
Replace L with (2W-5)
(2W-5) + W = 37
3W = 37 + 5
3W = 42
W = 42/3
W = 14 cm is the original width
Find L
L = 2(14) - 5
L = 28 - 5
L = 23 cm is the original length
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find the area of original rectangle.
23 * 14 = 322 sq cm
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