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| Question 995494:  1.A city's current population is 158,144. If this represents an increase of 85% of the population 7 years ago, what was the city's population 7 years ago?
 2.The value of a currency appreciated by 25.60% of its value last month and then depreciated by 25.60% this month. By what percent did the currency appreciate or depreciate over the 2-month period?
 Answer by Theo(13342)
      (Show Source): 
You can put this solution on YOUR website! question 1: 
 current population is 158,144.
 this represents an increase of 85% of the population 7 years ago.
 x + .85 * x = 158144
 1.85x = 158144
 x = 158144/1.85 = 85483.
 population 7 years ago was 85483.
 
 question 2:
 
 x = value 2 months ago.
 y = value 1 month ago.
 z = current value.
 
 x + .256 * x = y
 y - .256 * y = z
 
 in the second equation for z, replace y with the value of y from the first equation for y.
 
 you get:
 
 z = y - .256 * y becomes:
 
 z = (x + .256 * x)  - .256 * (x + .256 * x)
 
 simplify this to get:
 
 z = 1.256 * x - .256 * (1.256 * x)
 
 simplify further to get:
 
 z = 1.256 * x - .321536 * x
 
 combine like terms to get:
 
 z = .934464 * x
 
 this means that the value of the current month is equal to .934464 * the value of 2 months ago.
 
 .934464 is equal to 1 - .065536.
 
 z = .934464 * x is therefore equivalent to z = x - .065536 * x.
 
 your net gain is equal to - .065536 * x which means that your net loss is equal to .065536 * x.
 
 .065536 * 100 is equal to 6.5536%.
 
 your value has depreciated by 6.5536%.
 
 put this into numbers and it's easier to see what i mean.
 
 you start with 1000, for example.
 
 in one month, that appreciates 25.6% to become equal to 1000 + .256 * 1000 = 1256
 
 in another month that depreciates 25.6% to become equal to 1256 - .256 * 1256 = 934.464
 
 you started with 1000 and you ended with 934.464.
 
 you took a net loss of 1000 - 934.464 = 65.536
 
 that's a net loss percent of 65.536 / 1000 = .065536 * 100 = 6.5536%.
 
 
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