SOLUTION: the area of a rectangle is (6x^2 +11x + 5) cm^2 the width is (x +1) what is the length of the rectangle

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: the area of a rectangle is (6x^2 +11x + 5) cm^2 the width is (x +1) what is the length of the rectangle      Log On


   

Question 995474: the area of a rectangle is (6x^2 +11x + 5) cm^2 the width is (x +1) what is the length of the rectangle
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
This is dividing x+1 into 6x^2+11x+5
=====================6x
==========================6x^2+6x, then subtract
===============================5x+5
x+1 goes into that 5 times,
so the length is (6x+5)cm
Their product is 6x^2+11x+5 cm^2