SOLUTION: My problem is to write the equation in standard and slop form (-4/9, -6) and (12/7, -6)

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Question 995452: My problem is to write the equation in standard and slop form (-4/9, -6) and (12/7, -6)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
given points:
(-4%2F9, -6) and (12%2F7, -6)

Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (4/9, -6) and (x2, y2) = (12/7, -6).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%28-6--6%29%2F%2812%2F7-4%2F9%29+=+0.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 0%2A4%2F9+%2Bb+=+-6. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=-6-0%2A4%2F9+=+-6.

y=(0)x + (-6)

Your graph:



so, you have a horizontal line y=-6