SOLUTION: A company buysa copier for $10,000. The value of the copier is $10,000(1-n/20) after n years. After how many years will the value of the copier be $6,500?

Algebra ->  Rate-of-work-word-problems -> SOLUTION: A company buysa copier for $10,000. The value of the copier is $10,000(1-n/20) after n years. After how many years will the value of the copier be $6,500?      Log On


   

Question 99543: A company buysa copier for $10,000. The value of the copier is $10,000(1-n/20) after n years. After how many years will the value of the copier be $6,500?
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
A company buys a copier for $10,000. The value of the copier is
$10000%281-n%2F20%29 after n years. After how many years will 
the value of the copier be $6,500?

The formula for V, the value, after n years, is 

V+=+10000%281-n%2F20%29

So plug in 6500 for V

6500+=+10000%281-n%2F20%29

Divide both sides by 10000

6500%2F10000+=+1-n%2F20

0.65=1-n%2F20

Clear of fraction by multiplying through by 20:

20%280.65%29=20%281%29-20%28n%2F20%29

13=20-n

Add n to both sides:

n%2B13=20

Add -13 to both sides:

n=20-13

n=7

The answer is 7.  After 7 years the copier 
will be worth $6500.

Edwin