SOLUTION: The average of 4 positive numbers is 8. If all the numbers are less than 10, none of these numbers could be... A. 2 B. 3.5 C. 8 D. 9.9

Algebra ->  Finance -> SOLUTION: The average of 4 positive numbers is 8. If all the numbers are less than 10, none of these numbers could be... A. 2 B. 3.5 C. 8 D. 9.9      Log On


   



Question 995343: The average of 4 positive numbers is 8. If all the numbers are less than 10, none of these numbers could be...
A. 2
B. 3.5
C. 8
D. 9.9

Answer by ikleyn(52908) About Me  (Show Source):
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The average of 4 positive numbers is 8. If all the numbers are less than 10, none of these numbers could be...
A. 2
B. 3.5
C. 8
D. 9.9
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Answer. . . . None of these numbers could be  2.

Solution

Let these four numbers be  a,  b,  c  and  d.

Since the average  (I mean, arithmetic average)  of  4  positive numbers is  8,  their sum is  4*8 = 32.

If some of the numbers,  let say,  a,  is 2,  then

a + b + c + d = 2 + (b + c + d) < 32,

since  (b + c + d)  is less than  3*10 = 30,  according to the condition.

Thus from one side,

a + b + c + d = 32.

From the other side

a + b + c + d < 32.

Contradiction.

This proof works for "2" and does not work for other numbers of the cases B, C and D.