SOLUTION: how many liters of a 70% acid solution must be mixed with a 30% acid solution to get 240 L of a 60% acid solution?

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Question 995254: how many liters of a 70% acid solution must be mixed with a 30% acid solution to get 240 L of a 60% acid solution?
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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S=amount of 70% solution: T=amount of 30% solution
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S+T=240L
T=240L-S
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(0.70)S+(0.30)T=(0.60)(240L)
(0.70)S+(0.30)(240L-S)=144L
0.70S+72L-0.30S=144L
0.40S=72
S=180L
T=240L-S=240L-180L=60L
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ANSWER: 180 liters of 70% solution mixed with 60 liters
of 30% solution yields 240 liters of 60% solution.
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CHECK:
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(0.70)S+(0.30)T=(0.60)(240L)
(0.70)180L+(0.30)60L=(0.60)(240L)
126L+18L=144L
144L=144L
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