SOLUTION: State the number of real roots for 2x^2+6x-3=o

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Question 995242: State the number of real roots for 2x^2+6x-3=o
Answer by ikleyn(52817) About Me  (Show Source):
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State the number of real roots for 2x^2+6x-3=0.
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The discriminant d = b%5E2+-+4%2Aa%2Ac is 6%5E2+-+4%2A2%2A%28-3%29 = 36 + 24 = 60 is positive, so the equation has two real roots.