SOLUTION: One number is four more than the other. The square of the smallest number increased by three times the larger is 66. Find the two numbers

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Question 995241: One number is four more than the other. The square of the smallest number increased by three times the larger is 66. Find the two numbers
Answer by macston(5194) About Me  (Show Source):
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S=smaller number; L=larger number=S+4
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S%5E2%2B3L=66
S%5E2%2B3%28S%2B4%29=66
S%5E2%2B3S%2B12=66
S%5E2%2B3S-54=0
%28S%2B9%29%28S-6%29=0
S%2B9=0 OR S-6=0
S=-9 OR S=6
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L=S+4
L=-9+4 OR L=6+4
L=-5 OR L=10
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ANSWER: The two numbers are -9 and -5 or 6 and 10.