SOLUTION: Find two whole numbers whose product is 147 and whose quotient is 3

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Question 99515This question is from textbook
: Find two whole numbers whose product is 147 and whose quotient is 3 This question is from textbook

Answer by doukungfoo(195) About Me  (Show Source):
You can put this solution on YOUR website!
Ok the object is to find two whole numbers. Lets call those numbers x and y.
Now the question states that these two numbers ( x and y) have a product that equals 147.
lets write that as and equation
%28x%29%28y%29=147
We are also told that these numbers ( x and y ) have a quotient of 3
written as an equation we get this:
x%2Fy=3
Ok lets take a look at the first equation:
%28x%29%28y%29=147
We can set it in terms of x by dividing both sides by y like this:
%28xy%29%2F%28y%29=147%2Fy
x=147%2Fy
Now we have x equal to 147 divided by y so if we take the second equation
x%2Fy=3
and replace the x with 147/y we get this:
%28147%2Fy%29%2Fy=3
now we can solve for y
first multiply both sides by y
%28y%29%28%28147%2Fy%29%2Fy%29=3%28y%29
147%2Fy=3y
next multiply both sides by y again
147=3y%5E2
now divide both sides by 3
49=y%5E2
finally solve for y by taking the square root of both sides
sqrt%2849%29=sqrt%28y%5E2%29
7=y
Now that we have found y equals 7 just replace the y in %28x%29%28y%29=147 with 7
and solve for x
%28x%29%287%29=147
%287x%29%2F7=147%2F7
x=21
So now we have found two numbers 21 and 7
Their product is 147
%2821%29%287%29=147
and their quotient is 3
21%2F7=3