SOLUTION: John has $6.10 in dimes and quarters. If he has 37 coins in total how many of each does he have

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Question 995093: John has $6.10 in dimes and quarters. If he has 37 coins in total how many of each does he have
Answer by lwsshak3(11628) About Me  (Show Source):
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John has $6.10 in dimes and quarters. If he has 37 coins in total how many of each does he have
let x=number of dimes
37-x= number of quarters
.10x+.25(37-x)=6.10
.10x+9.25-.25x=6.10
.15x=3.15
x=21
37-x=16
number of dimes=21
number of quarters=16