Question 995038: Find cosθ and sinθ, given that tanθ=3, and 180° < θ < 270°
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find cosθ and sinθ, given that tanθ=3, and 180° < θ < 270°
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Note:: t is in QII where x is negative and y is negative
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By definition tan = y/x = 3/1
Therefore y = -3 and x = -1
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r = sqrt[3^2+1^2] = sqrt(10)
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cos = x/r = -1/sqrt(10)
sin = y/r = -3/sqrt(10)
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Cheers,
Stan H.
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