SOLUTION: Consider the two events A and B with P(A) = 0.4 and P(B) = 0.3. (a) If A and B are independent then compute the probability that
(i) Both A and B happen.
(ii) A or B happen.
(ii
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-> SOLUTION: Consider the two events A and B with P(A) = 0.4 and P(B) = 0.3. (a) If A and B are independent then compute the probability that
(i) Both A and B happen.
(ii) A or B happen.
(ii
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Question 994977: Consider the two events A and B with P(A) = 0.4 and P(B) = 0.3. (a) If A and B are independent then compute the probability that
(i) Both A and B happen.
(ii) A or B happen.
(iii) Neither A nor B happen.
(b) Now answer parts (i)-(iii) when the events A and B are mutually exclusive instead of being independent. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Probability is 0.12 that both happen. You multiply.
Neither happens is 0.6*0.7=0.42. You take the complement of each and multiply
A or B happens. 0.4+0.3-P(both)=0.7-0.12=0.58
If they are mutually exclusive, then
probability is 0 that both happen. They can't by definition.
probability A or B happens is 0.7. There is no double counting.
probability neither happens is 0.3.
