SOLUTION: Quesiton - Find an equation of the line satisfying the given conditions. Through (6,8) and perpendicular to y = 2x - 3

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Question 99495: Quesiton - Find an equation of the line satisfying the given conditions.
Through (6,8) and perpendicular to y = 2x - 3
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line


Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of 2, you can find the perpendicular slope by this formula:

m%5Bp%5D=-1%2Fm where m%5Bp%5D is the perpendicular slope


m%5Bp%5D=-1%2F%282%2F1%29 So plug in the given slope to find the perpendicular slope



m%5Bp%5D=%28-1%2F1%29%281%2F2%29 When you divide fractions, you multiply the first fraction (which is really 1%2F1) by the reciprocal of the second



m%5Bp%5D=-1%2F2 Multiply the fractions.


So the perpendicular slope is -1%2F2



So now we know the slope of the unknown line is -1%2F2 (its the negative reciprocal of 2 from the line y=2%2Ax-3). Also since the unknown line goes through (6,8), we can find the equation by plugging in this info into the point-slope formula

Point-Slope Formula:

y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope and (x%5B1%5D,y%5B1%5D) is the given point



y-8=%28-1%2F2%29%2A%28x-6%29 Plug in m=-1%2F2, x%5B1%5D=6, and y%5B1%5D=8



y-8=%28-1%2F2%29%2Ax%2B%281%2F2%29%286%29 Distribute -1%2F2



y-8=%28-1%2F2%29%2Ax%2B6%2F2 Multiply



y=%28-1%2F2%29%2Ax%2B6%2F2%2B8Add 8 to both sides to isolate y

y=%28-1%2F2%29%2Ax%2B6%2F2%2B16%2F2 Make into equivalent fractions with equal denominators



y=%28-1%2F2%29%2Ax%2B22%2F2 Combine the fractions



y=%28-1%2F2%29%2Ax%2B11 Reduce any fractions

So the equation of the line that is perpendicular to y=2%2Ax-3 and goes through (6,8) is y=%28-1%2F2%29%2Ax%2B11


So here are the graphs of the equations y=2%2Ax-3 and y=%28-1%2F2%29%2Ax%2B11




graph of the given equation y=2%2Ax-3 (red) and graph of the line y=%28-1%2F2%29%2Ax%2B11(green) that is perpendicular to the given graph and goes through (6,8)