SOLUTION: The path when a stone is thrown can be modelled by y=-16 x2 +10x+4,where y (in feet) is the height of the stone x seconds after it is released.
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Quadratic Equations and Parabolas
-> SOLUTION: The path when a stone is thrown can be modelled by y=-16 x2 +10x+4,where y (in feet) is the height of the stone x seconds after it is released.
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Question 994891: The path when a stone is thrown can be modelled by y=-16 x2 +10x+4,where y (in feet) is the height of the stone x seconds after it is released. Answer by Alan3354(69443) (Show Source):
