SOLUTION: A train leaves a station and travels north at a speed of 30 mph. Five hours later, a second train leaves on a parallel track and travels north at 105 mph. How far from the station
Question 994849: A train leaves a station and travels north at a speed of 30 mph. Five hours later, a second train leaves on a parallel track and travels north at 105 mph. How far from the station will they meet? Found 2 solutions by lwsshak3, josgarithmetic:Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! A train leaves a station and travels north at a speed of 30 mph. Five hours later, a second train leaves on a parallel track and travels north at 105 mph. How far from the station will they meet?
let x=travel time of 2nd train
x+5=travel time of 1st train
distance=travel time*speed
30(x+5)=105x
30x+150=105x
75x=150
x=2
105x=30(x+5)=210
How far from the station will they meet? 210 mi
You can put this solution on YOUR website! A very common type of travel rates exercise problem. This will be a general solution for just that reason.
r speed of early, slow train
R speed of fast, late train
t travel time for fast train, left later than slow train
h amount of time passed before fast train departed
d the catch-up distance
TRAIN speed time distance
Early Slow r t+h d
Late Fast R t d
Question is to solve for d.
The unknown variables are t and d, but you do not need to find a value for t. (Unless you WANT to).
Initial system of equations,
- ---The answer in symbolic form.
Your question gives you the values to use:
Substitute these and evaluate d:
(