SOLUTION: Find 2 consecutive even integers such that their sum is equal to the difference of 3 times the larger and 2 times the smaller (This is let statements)

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Question 994803: Find 2 consecutive even integers such that their sum is equal to the difference of 3 times the larger and 2 times the smaller
(This is let statements)
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
n is any integer.
Your integers begin as 2n and 2n+2.

SUM: 2n%2B2n%2B2=4n%2B2
Difference Description: 3%282n%2B2%29-2%282n%29=6n%2B6-%284n%29=4n%2B6
FULL DESCRIPTION: highlight%284n%2B2=4n%2B6%29

Impossible because false statement.
The description needs to be better.

Maybe the difference description part should be 2%2A2n-3%282n%2B2%29=4n-6n-6=-2n-6.
The equation for the full description would be highlight_green%284n%2B2=-2n-6%29;
Maybe this would be workable.
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4n%2B2n%2B2=-6
6n%2B2=-6
6n=-6-2
6n=-8
highlight_green%28n=-4%2F3%29
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This still will not work, because your 2n and 2n+2 are NOT INTEGERS.

NO SOLUTION

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

Find 2 consecutive even integers such that their sum is equal to the difference of 3 times the larger and 2 times the smaller
(This is let statements) 
Let the smaller integer be S

Then larger integer is: S + 2

From the description, we get: S + S + 2 = 3(S + 2) - 2S

Solve this equation to determine the value of S, the smaller integer

Add 2 to this smaller integer to get the larger integer

You should get: highlight_green%28system%28Smaller+=+4%2CLarger+=+6%29%29