SOLUTION: Please help me with these problems. I tried this and came up with -3x^3+12x 1. The polynomial of degree 5, P(x) has leading coefficient 1, has roots of multiplicity 2 at x=5 a

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Please help me with these problems. I tried this and came up with -3x^3+12x 1. The polynomial of degree 5, P(x) has leading coefficient 1, has roots of multiplicity 2 at x=5 a      Log On


   

Question 994799: Please help me with these problems. I tried this and came up with -3x^3+12x
1. The polynomial of degree 5, P(x) has leading coefficient 1, has roots of multiplicity 2 at x=5 and x=0 , and a root of multiplicity 1 at x=−2. Find a possible formula for P(x).
2.The polynomial of degree 3 , P(x) , has a root of multiplicity 2 at x=5 and a root of multiplicity 1 at x=−1 . The y -intercept is y=−15 .
Find a formula for P(x).

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
leading coefficient 1, has roots of multiplicity 2 at x=5 and x=0 , and a root of
multiplicity 1 at x=-2.

P%28x%29=%28x-5%29%5E2%28x%29%5E2%28x-%28-2%29%29
highlight_green%28P%28x%29=x%5E2%2A%28x-5%29%5E2%28x%2B2%29%29

Multiply and put into general form if you need.