Question 994782: using n,n+2, n+4 for three consecutive even integers,express each statement as an equation,then find the integers.
twenty times the sum of the second and the final equals 3 more thanthe first.
Found 2 solutions by CubeyThePenguin, MathTherapy:
Answer by CubeyThePenguin(3113)   (Show Source):
You can put this solution on YOUR website! 20(n + 2 + n + 4) = 3 + n
20(2n + 6) = n + 3
40n + 120 = n + 3
39n = -117
n = -3
the integers are -3, -1, and 1.
I appreciate you looking out for mistakes in the posts I make, and I would appreciate them more if you would provide a solution in most of the posts where you proclaim that someone's answer is wrong.
I solve all the old problems so you don't have to. That's all.
"second and final equals 3 more than the first"
-1 + 1 = 0
3(0) = 0
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website! using n,n+2, n+4 for three consecutive even integers,express each statement as an equation,then find the integers.
twenty times the sum of the second and the final and the third equals 3 more thanthe first.
NO SOLUTIONS!!
Why does the person who responded make so MANY MISTAKES with the numerous number of these problems that he has attempted?
Plus, doesn't he realize that all these problems that he's now doing for these people were asked MANY, MANY years ago?
And that there may be a valid reason why they were not responded to all these years!
What is he trying to prove? That in a month he can respond to 2,000 math problems on ALGEBRA.com?
I wonder!!!
How will you learn if I tell you where you're making all these mistakes. Is it not for you to make sure you do a good and impressive job,
since these people are asking for OUR help? A piece of advice I have for you is to READ the problem and try to determine why I stated that there are NO SOULTIONS!
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