Question 994670: ten years ago a father was six time as old as his son. After 10 years, he will be twice as old as his son. determine their present ages.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! ten years ago a father was six time as old as his son. After 10 years, he will be twice as old as his son. determine their present ages.
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Equations:
f-10 = 6(s-10)
f+10 = 2(s+10)
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Rearrange::
f - 6s = -50
f - 2s = 10
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Subtract and solve for "s"::
4s = 40
s = 10 yrs (son's age now)
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Solve for "f":
f - 2s = 10
f-20 = 10
f = 30 yrs (father's age now)
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Cheers,
Stan H.
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