SOLUTION: 8=4(3c+5)

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Question 99463This question is from textbook Algerbra 1
: 8=4(3c+5) This question is from textbook Algerbra 1

Answer by doukungfoo(195) About Me  (Show Source):
You can put this solution on YOUR website!
8=4%283c%2B5%29
First simplify the equation by removing the parentheses.
To do this multiply 4 times 3c and then 4 times 5.
Now the equation looks like this:
8=12c%2B20
Next move all terms with the c variable to one side of the equal sign
and all terms without a variable to the opposite side of the equal sign.
This is done by subtracting 20 from both sides of the equal sign.
8-20=12c%2B20-20
8-20 equals -12 and 20-20 equals zero so now we have this:
-12=12c
Now to solve for c divide both sides of the equal sign by 12
%28-12%29%2F12=%2812c%29%2F%2812%29
-12 divided by 12 equals -1 and 12c divided by 12 equals c
so c+=+-1
To check the answer replace c with -1 in the original equation:
8=4%283c%2B5%29
8=4%283%28-1%29%2B5%29
8=4%28-3%2B5%29
8=4%28%2B2%29
8=8