SOLUTION: in a school x no of boys is 40 percent more than girls and in a school y no of girls is 50 percent more than boys if 50 percent of boys in school x =70 percent of girls in school y

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Question 994629: in a school x no of boys is 40 percent more than girls and in a school y no of girls is 50 percent more than boys if 50 percent of boys in school x =70 percent of girls in school y what is the ratio between no of students of school x and y?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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"in a school x no of boys is 40 percent more than girls,"
lets try this with some values,
let b = no. of boys in the x school
let g = no. of girls
x = 360 total students in x school
then
b + g = 360
given statement
b = 1.4g
Replace b with 1.4g
1.4g + g = 360
2.4g = 360
g = 360/2.4
g = 150 girls in x school
and
360 - 150 = 210 boys in x school
:
if 50 percent of boys in school x = 70 percent of girls in school y,
let f = no. of girls in school y
.5(210) = .7f
105 = .7f
f = 105/.7
f = 50 girls in school y
:
It also says,"in a school y no of girls is 50 percent more than boys."
let m = no. of boys in school y
1.5m = 50
m = 50/1.5
m = 150 boys in school y
:
Find the total students in school y
50 + 150 = 200
:\
what is the ratio between no of students of school x and y?
360%2F200 reduces to a ratio of 9:5