SOLUTION: THE AVERAGE TIME IT TAKES SOMEONE TO FINISH THE 2.4 MILE SWIM AT IRONMAN LOUISVILLE IS APPROXIMATELY 86 MIN WITH STANDARD DEVIATION OF 10 MIN. ASSUME THE DISTRIBUTION IS APPROX NOR
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-> SOLUTION: THE AVERAGE TIME IT TAKES SOMEONE TO FINISH THE 2.4 MILE SWIM AT IRONMAN LOUISVILLE IS APPROXIMATELY 86 MIN WITH STANDARD DEVIATION OF 10 MIN. ASSUME THE DISTRIBUTION IS APPROX NOR
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Question 994551: THE AVERAGE TIME IT TAKES SOMEONE TO FINISH THE 2.4 MILE SWIM AT IRONMAN LOUISVILLE IS APPROXIMATELY 86 MIN WITH STANDARD DEVIATION OF 10 MIN. ASSUME THE DISTRIBUTION IS APPROX NORMAL.
WHAT IS PROBABILITY THAT A RANDOMLY SELECTED WILL SWIM UNDER 60 MINUTES?
I DO NOT KNOW WHAT FORMULA TO USE FOR THIS.. MY GUESS WAS X-MEAN/STAND DEVIATION
SOMETHING LIKE P(X<60) 86-60/10=2.6 BUT I HAVE FEELING I AM DOING IT WRONG. CAN YOU PLEASE SHOW ME IN STEPS?
THANKS Answer by solver91311(24713) (Show Source):
