SOLUTION: Find two consecutive even integers such that four times the first plus two times the second is 40

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Question 994422: Find two consecutive even integers such that four times the first plus two times the second is 40
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Lets call the first integer x, and the second integer is to be a consecutive even integer, so it must be x%2B2
if four times the first plus two times the second is 40, we have
4%2Ax%2B2%28x%2B2%29=40...solve for x
4x%2B2x%2B4=40
6x=40-4
6x=36
x=36%2F6
highlight%28x=6%29=>the first integer
x%2B2=6%2B2=>highlight%28x%2B2=8%29=>the second integer