SOLUTION: My son is in 8th grade he is learning about solving linear equations and properties I have been helping him identity the steps and he got an equation that stumped all 3 of us him m
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Question 994192: My son is in 8th grade he is learning about solving linear equations and properties I have been helping him identity the steps and he got an equation that stumped all 3 of us him me and my husband
2/4z+4=1/2/3z-1
Our issues lie in the 1/2 in the numerator we have tried to isolate the z and just getting stumped any advice or guidance on this step apprecciated Found 2 solutions by stanbon, MathTherapy:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 2/(4z+4)=(1/2)/(3z-1)
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Cross-multiply to get:
2(3z-1) = (1/2)(4z+4)
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6z-2 = 2z+2
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Subtract 2z from both sides:
Add 2 to both sides::
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4z = 4
z = 1
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Pls. let me know if that is too confusing.
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Cheers,
Stan H.
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You can put this solution on YOUR website!
My son is in 8th grade he is learning about solving linear equations and properties I have been helping him identity the steps and he got an equation that stumped all 3 of us him me and my husband
2/4z+4=1/2/3z-1
Our issues lie in the 1/2 in the numerator we have tried to isolate the z and just getting stumped any advice or guidance on this step apprecciated
You need to use parentheses
I presume this is the equation: , with , and . If it is, then: ----- Cross-multiplying --------- Cross-multiplying
12z - 4 = 4z + 4
12z - 4z = 4 + 4
8z = 8 , or
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