SOLUTION: The length of a rectangle is 4in. Greater than its width. The perimeter of the rectangle is 24in. Find the dimensions of the rectangle.
W=width l=length
I know that to find t
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-> SOLUTION: The length of a rectangle is 4in. Greater than its width. The perimeter of the rectangle is 24in. Find the dimensions of the rectangle.
W=width l=length
I know that to find t
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Question 994173: The length of a rectangle is 4in. Greater than its width. The perimeter of the rectangle is 24in. Find the dimensions of the rectangle.
W=width l=length
I know that to find the length it's 4+w(2)
I know that the width would be 2w
I just need help checking and I'm wondering if I'm missing anything Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
W=width; L=length=W+4
.
P=2(L+W)
24in=2((W+4)+W)
12in=2W+4
8in=2W
4in=W
ANSWER 1: The width is 4 inches.
.
L=W+4
L=4+4=8
ANSWER 2: The length is 8 inches.
.
CHECK:
.
P=2(L+W)
24in=2(8in+4in)
24in=2(12in)
24in=24in
